[Python] 문자열 내 p와 y의 개수

[나의 풀이]

def solution(s):
    s = s.lower()
    countP = 0
    countY = 0
    for i, j in enumerate(s):
        print(i, j)
        if j == "p":
            countP += 1
        elif j == "y":
            countY += 1
    print(countP)
    print(countY)
    if countP == countY:
        return True
    else:
        return False
print(solution("pPooY"))

[다른 풀이]

def numPY(s):
    return s.lower().count('p') == s.lower().count('y')

from collections import Counter
def numPY(s):
    c = Counter(s.lower())
    return c['y'] == c['p'] 

def numPY(s):
    if(s.upper().count('P')==s.upper().count('Y')):
        return True
    return False