workSpace/ALGORITHM
[Python] x만큼 간격이 있는 n개의 숫자
J o e
2020. 12. 20. 13:14
[나의 풀이]
def solution(x, n):
answer = []
for i in range(n):
a = x * i + x
answer.append(a)
return answer
[다른 풀이]
def number_generator(x, n):
return [i * x + x for i in range(n)]
def number_generator(x, n):
return [i for i in range(x, x*n+1, x)]
def number_generator(x, n):
t = list(range(x, n*x+1, x))
return t